3t^2-26t=40

Solution for 3t^2-26t=40 equation:

3t^2-26t=40

We move all terms to the left:

3t^2-26t-(40)=0

a = 3; b = -26; c = -40;
Δ = b2-4ac
Δ = -262-4·3·(-40)
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1156}=34$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-34}{2*3}=\frac{-8}{6}
=-1+1/3
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+34}{2*3}=\frac{60}{6}
=10
$